From: Spike Jones (spike66@attglobal.net)
Date: Tue Apr 03 2001 - 00:32:20 MDT
Lee Corbin wrote:
> equations "ab - cd = 1" or "a^2 + b^2 = c^2 + 1". I worry
> that the first may not even be possible---
Oh by the way, ab - cd = 1 also has infinitely many solutions:
where a = b and c = a-1 and d = a+1, a,b,c,d all integers, then
ab - cd = a^2 - (a-1)(a+1)= a^2 - (a^2 -1) = 1.
spike
This archive was generated by hypermail 2.1.5 : Sat Nov 02 2002 - 08:06:48 MST