From: hal@finney.org
Date: Sun Sep 03 2000 - 14:31:37 MDT
Eugene writes:
> Let's assume a 1 m^2 PV panel, with the average insolation of 0.5
> kW/m^2. Let's say the efficiency is 10%, so it generates 0.05 kW (50
> W) on the average. Let's say we do get 10 years effective life time
> out of it, with ~10 h hourly insolation. We're getting 10 y * 365 d
> *10 h =36500 hours, at 0.05 kW. This is rougly 2 kWh, right?
No, 1000 times greater. 36500 hours * .05 kW = 1825 kWH.
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