<artillo5@cs.com> wrote:
What if a second "monitoring particle" (I don't know what type
of particle that might be) were used and its state was affected
somehow but the change in the entangled particle?
--------------
Neutral kaons [e + , e - >> mesons >> K 0 , K 0 bar]
are smart. That is because the decay mode of the first kaon
[i. e. as pi+, pi-] implies that the other kaon can not decay,
at the same time, in the same mode [but, i.e., as pi+, pi-, pi zero]
Thus you get the correlation (entanglement)
|psi> = 2 ^ (-1/2) ( |K 0> |K 0 bar> - |K 0 bar> |K 0> )
and, at the same time, the anticorrelation, due to the
different decay modes.
That's something, but not so much.
This archive was generated by hypermail 2b30 : Sat May 11 2002 - 17:44:13 MDT