Re: extropian almost perfect odd number team captures world record

From: spike66 (spike66@attbi.com)
Date: Fri Jun 07 2002 - 01:24:09 MDT


>
>
>On Thu, 6 Jun 2002, spike66 wrote:
>
>(is this wicked cool, or what?)
>
One who likes wisecracks as much as I do wrote:

>Python yes, but not too many people have a number fetish ;P
>
Those who get all hung up on whips, feathers and rubber boots
do not know what they are missing. Numbers can produce an
orgasms that can be sustained for weeks.

Boy am I tired.

CurtAdams@aol.com wrote:

>Time to think about writing for the Journal of Experimental Mathematics? Do
>you have plots of best number vs size of number, or any other intriguing
>relationships to set off the number theorists?
>
I do.

As Jeff Davis is fond of quoting, everything is hard until
you know how to do it. Today I think I figured out how to do
it, which I will now share.

The general technique for finding ever better numbers is by
starting out with a sequence of prime numbers such as
3,5,7 and 11 (others will work, but this is a very good one)
then finding the next number in the sequence by taking
the product of the previous three in the sequence.

For instance, in the 3,5,7,11 example, take
5*7*11 = 385, then increment to the next largest prime,
which is 389.

The product of 3*5*7*11*389 will be a really good number,
but an even better one can be found by taking
7*11*389=29953, and incrementing to the next largest prime,
29959. The new record will be 3*5*7*11*389*29959.

The one I found tonight has the seventh prime factor of
128194559. Furthermore, the eighth prime factor of a still better
good number is the nearest prime to 1493986278130039.

My gift to the extropian math fetishers is to offer the opportunity
to snag the world record for the best odd number. Simply find
the nearest prime to 1493986278130039, then multiply
3*5*7*11*389*29953*128194559*(nearest prime to
1493986278130039).

Lee Corbin generously showed me the formula for the
sum of the factors of a product of unique prime factors is:
 (F1+1)*(F2+1)*...*(Fn+1) - F1*F2*...*Fn.

Somebody check my work and do share the code you
used. Have we any python code jockeys that want to
look at this?

Who wants to collaborate on a paper for the
Journal of Experimental Mathematics? spike



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