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Date: Tue, 18 Aug 2015 17:43:48 +0530
Message-ID: <CAED3CWgTOMFgaM6bBfU0Dn-R0NrdrhGAQo34wHEneYkTtB4Opg@mail.gmail.com>
From: Upal Chakraborty <bitcoin@upalc.com>
To: bitcoin-dev@lists.linuxfoundation.org
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Subject: [bitcoin-dev] Dynamically Controlled Bitcoin Block Size Max Cap
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Regarding:
http://lists.linuxfoundation.org/pipermail/bitcoin-dev/2015-August/010295.html


I am arguing with the following statement here...

*I see problems to this approach. The biggest one I see is that a miner
> with 11% of hash power could sabotage block size increases by only ever
> mining empty blocks.*


First, I would like to argue from economics' point of view. If someone
wants to hold back the block size increase with 11% hash power by mining
empty blocks, he has to sacrifice Tx fees, which is not economical. 11%
hash power will most likely be a pool and pool miners will find out soon
that they are losing Tx fees because of pool owner's intention. Hence,
they'll switch pool and pool owner will lose out. This is the same reason
why 51% attack will never happen, even if a pool gets more than 51% hash
power.


Next, I would like to propose a slightly modified technical solution to
this problem in algorithmic format...

If more than 50% of block's size, found in the first 2000 of the last
difficulty period, is more than 90% MaxBlockSize
         Double MaxBlockSize
Else if more than 90% of block's size, found in the first 2000 of the last
difficulty period, is less than 50% MaxBlockSize
         Half MaxBlockSize
Else
         Keep the same MaxBlockSize

This is how, those who want to stop increase, need to have more than 50%
hash power. Those who want to stop decrease, need to have more than 10%
hash power, but must mine more than 50% of MaxBlockSize in all blocks. In
this approach, not only miners, but also the end user have their say.
Because, end users will fill up the mempool, from where miners will take Tx
to fill up the blocks. Please note that, taking first 2000 of the last 2016
blocks is important to avoid data discrepancy among different nodes due to
orphan blocks. It is assumed that a chain can not be orphaned after having
16 confirmation.

Looking for comments.

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<div dir=3D"ltr">Regarding:=C2=A0<a href=3D"http://lists.linuxfoundation.or=
g/pipermail/bitcoin-dev/2015-August/010295.html">http://lists.linuxfoundati=
on.org/pipermail/bitcoin-dev/2015-August/010295.html</a><div><br><div><br><=
/div><div>I am arguing with the following statement here...</div><div><br><=
/div><div><blockquote class=3D"gmail_quote" style=3D"margin:0px 0px 0px 0.8=
ex;border-left-width:1px;border-left-color:rgb(204,204,204);border-left-sty=
le:solid;padding-left:1ex"><i>I see problems to this approach. The biggest =
one I see is that a miner with 11% of hash power could sabotage block size =
increases by only ever mining empty blocks.</i></blockquote><div><br></div>=
<div><br></div><div>First, I would like to argue from economics&#39; point =
of view. If someone wants to hold back the block size increase with 11% has=
h power by mining empty blocks, he has to sacrifice Tx fees, which is not e=
conomical. 11% hash power will most likely be a pool and pool miners will f=
ind out soon that they are losing Tx fees because of pool owner&#39;s inten=
tion. Hence, they&#39;ll switch pool and pool owner will lose out. This is =
the same reason why 51% attack will never happen, even if a pool gets more =
than 51% hash power.</div></div></div><div><br></div><div><br></div><div>Ne=
xt, I would like to propose a slightly modified technical solution to this =
problem in algorithmic format...</div><div><br></div><div>If more than 50% =
of block&#39;s size, found in the first 2000 of the last difficulty period,=
 is more than 90% MaxBlockSize</div><div>=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0=
Double MaxBlockSize</div><div><div>Else if more than 90% of block&#39;s siz=
e, found in the first 2000 of the last difficulty period, is less than 50% =
MaxBlockSize</div><div>=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0Half MaxBlockSize<=
/div></div><div>Else</div><div>=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0Keep the s=
ame MaxBlockSize</div><div><br></div><div>This is how, those who want to st=
op increase, need to have more than 50% hash power. Those who want to stop =
decrease, need to have more than 10% hash power, but must mine more than 50=
% of MaxBlockSize in all blocks. In this approach, not only miners, but als=
o the end user have their say. Because, end users will fill up the mempool,=
 from where miners will take Tx to fill up the blocks. Please note that, ta=
king first 2000 of the last 2016 blocks is important to avoid data discrepa=
ncy among different nodes due to orphan blocks. It is assumed that a chain =
can not be orphaned after having 16 confirmation.</div><div><br></div><div>=
Looking for comments.</div><div><br></div><div><br></div><div><br></div><di=
v><br></div></div>

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