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Harding" , Bitcoin Protocol Discussion From: ZmnSCPxj Reply-To: ZmnSCPxj Message-ID: In-Reply-To: <20200628121517.f3l2mjcy7x4566v3@ganymede> References: <20200628121517.f3l2mjcy7x4566v3@ganymede> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8 Content-Transfer-Encoding: quoted-printable Cc: Matan Yehieli , Itay Tsabary Subject: Re: [bitcoin-dev] MAD-HTLC X-BeenThere: bitcoin-dev@lists.linuxfoundation.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: Bitcoin Protocol Discussion List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Mon, 29 Jun 2020 18:05:19 -0000 Good morning Dave, et al., > > Myopic Miners: This bribery attack relies on all miners > > > > > > being rational, hence considering their utility at game conclu- > > sion instead of myopically optimizing for the next block. If > > a portion of the miners are myopic and any of them gets to > > create a block during the first T =E2=88=92 1 rounds, that miner would > > include Alice=E2=80=99s transaction and Bob=E2=80=99s bribery attempt w= ould > > have failed. > > In such scenarios the attack succeeds only with a certain > > probability =E2=80=93 only if a myopic miner does not create a block > > in the first T =E2=88=92 1 rounds. The success probability therefore > > decreases exponentially in T . Hence, to incentivize miners > > to support the attack, Bob has to increase his offered bribe > > exponentially in T . > > This is a good abstract description, but I think it might be useful for > readers of this list who are wondering about the impact of this attack > to put it in concrete terms. I'm bad at statistics, but I think the > probability of bribery failing (even if Bob offers a bribe with an > appropriately high feerate) is 1-exp(-b*h) where `b` is the number of > blocks until timeout and `h` is a percentage of the hashrate controlled > by so-called myopic miners. Given that, here's a table of attack > failure probabilities: > > "Myopic" hashrate > B 1% 10% 33% 50% > l +--------------------------------- > o 6 | 5.82% 45.12% 86.19% 95.02% > c 36 | 30.23% 97.27% 100.00% 100.00% > k 144 | 76.31% 100.00% 100.00% 100.00% > s 288 | 94.39% 100.00% 100.00% 100.00% > > So, if I understand correctly, even a small amount of "myopic" hashrate > and long timeouts---or modest amounts of hashrate and short > timeouts---makes this attack unlikely to succeed (and, even in the cases > where it does succeed, Bob will have to offer a very large bribe to > compensate "rational" miners for their high chance of losing out on > gaining any transaction fees). > > Additionally, I think there's the problem of measuring the distribution > of "myopic" hashrate versus "rational" hashrate. "Rational" miners need > to do this in order to ensure they only accept Bob's timelocked bribe if > it pays a sufficiently high fee. However, different miners who try to > track what bribes were relayed versus what transactions got mined may > come to different conclusions about the relative hashrate of "myopic" > miners, leading some of them to require higher bribes, which may lead > those those who estimated a lower relative hash rate to assume the rate > of "myopic" mining in increasing, producing a feedback loop that makes > other miners think the rate of "myopic" miners is increasing. (And that > assumes none of the miners is deliberately juking the stats to mislead > its competitors into leaving money on the table.) A thought occurs to me, that we should not be so hasty to call non-myopic s= trategy "rational". Let us consider instead "myopic" and "non-myopic" strategies in a populatio= n of miners. I contend that in a mixed population of "myopic" and "non-myopic" miners, t= he myopic strategy is dominant in the game-theoretic sense, i.e. it might e= arn less if all miners were myopic, but if most miners were non-myopic and = a small sub-population were myopic and there was no easy way for non-myopic= miners to punish myopic miners, then the myopic miners will end up earning= more (at the expense of the non-myopic miners) and dominate over non-myopi= c miners. Such dominant result should prevent non-myopic miners from arising in the f= irst place. The dominance results from the fact that by accepting the Alice transaction= , myopic miners are effectively deducting the fees earned by non-myopic min= ers by preventing the Bob transaction from being confirmable. On the other hand, even if the non-myopic miners successfully defer the Ali= ce transaction, the myopic miner still has a chance equal to its hashrate o= f getting the Bob transaction and its attached fee. Thus, myopic miners impose costs on their non-myopic competitors that non-m= yopic miners cannot impose their myopic competitors. If even one myopic miner successfully gets the Alice transaction confirmed,= all the non-myopic miners lose out on the Bob bribe fee. So I think the myopic strategy will be dominant and non-myopic miners will = not arise in the first place. Regards, ZmnSCPxj